Jump to content
SAU Community

Recommended Posts

i have this rb25det motor still in car, running so you can test drive it no problem before buying.

i am wanting to get a deposit before i take it out as i want the person who buys it to hear it running.

it has only had a run in tune professionally it made 126kw on 5psi and was shut off at 5000rpm as its just run in tune.

needs another 500km (already done 450) running in then drop oil,oil filter,replace spark plugs then a final tune. easily make over 250kw.easy.

i have receipts for over $4.200 worth of work. internal engine work.

engine has

nismo 550cc injectors. brand new o rings.

garret 25/40 turbo has been rebuilt

microtech computer (no afm)

adjustable cam gears.

asking

engine alone: 4k

engine with turbo, injectors, microtech: 6k

also have a r33 gearbox series 2 with cusco os clutch an cermic fly wheel can include this in a deal.

wanting $2.5k or $1.6k without clutch and flywheel.

only serious buyers please pm me if your really intertested or call me.

everything is still in the car so feel free to test everything out.

prices are negotiable if you put down a deposit.

call me on 0430078630

picture of receipt can be supplied over the comp or can see for real..

price is slightly neg. come and see it running and drive it if you like offer me a reasonable price and we can go from there

Internal mods/what was done:

Dismantle/degrease and inspect long engine

Bore and hone block

Grind cranksharft

Dismantle assemble and align rods

Blance in-line engine assembly

Hone rod bushes

Dismantle/clean/inspect and test oil pump

Remove and refit callery plugs

Recondtion cylinderhead

Assemble to long motor

Brand new engine parts

Forged piston kit (acl race series)

Second hand rods

Assorted gallery plugs and specialty sealants.

All done by Engine Workx in Winchelsea

  • 2 weeks later...
  • 2 weeks later...

mate do u want sell clutch seperately??????????????? hws thw condition, and is twin or single plate..?????????

well not at this stage no want to sell the engine first before i start stripping it. thanks for the interest

  • 2 weeks later...

MASSIVE PRICE DROP ONLY 3K FOR ENGINE ALONE RING ME IF YOU WANT ANY OTHER PARTS ADDED ON AND I CAN ILL MAKE YOU A GOOD DEAL

I'm interested in the whole motor, turbo and computer. Where abouts are you from?

melbourne ring me on 0430078630 and we can talk about it .

  • 2 weeks later...

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now


  • Similar Content

  • Latest Posts

    • Don't they cool down technically when you're sitting at a set of lights? 
    • The circuit if not a resistor divider is using an opamp to deliver a specific current normally. By maintaining the current as resistance changes, the voltage does too. Add to that, thermistors are normally non linear too,which can make creating a function impossible. Most uses of a thermistor people will utilise a lookup table to get the corresponding temperature.
    • On a scale of 1 to 10, how shit are the RE003's? (10 being ultra mega shit) Was hoping they'd be alright for a non-daily driven R32 that might get driven to Charnwood Macca's in the dry once a month, and maybe the odd hoon up and down the hills that pass for mountains in sunny Canberra.  Bob Jane currently running a "Buy 4 Get 1 Free" deal on RE003s and my brain can't comprehend anything else being value for money
    • Yeah, they look good. I should try to fit them on mine. But being a GTSt, the guard shape probably doesn't suit properly.
    • Nah, it's not a simple voltage divider. I'm not enough of an electronics guru to know how they make these circuits work. If I had a better idea of how the ECU's temperature measuring is done, I could then actually do as you want, which is turn that resistance chart into a voltage chart. But my approach has not worked. What I did was interpolate the sensor ohms values for the temperatures you listed, as you did not have any of them on a temperature ending in zero or 5. These are: °C ECU V sensor ohms (interpolated) 58 2.68 11.85 57 2.7 11.89 56 2.74 11.93 54 2.8 12.01 49 3.06 12.208 47 3.18 12.284 43 3.37 12.42 I then assumed 5V supply to the resister and calculated the voltage drop across the sensor for each of those, which is just 5 - the above voltages, and then calculated the current that must be flowing through the sensor. So you get:             Values in sensor °C ECU V sensor ohms (interpolated) Supply volts Volt drop Current 58 2.68 11.85     5 2.32 0.195781 57 2.7 11.89     5 2.3 0.19344 56 2.74 11.93     5 2.26 0.189438 54 2.8 12.01     5 2.2 0.183181 49 3.06 12.208     5 1.94 0.158912 47 3.18 12.284     5 1.82 0.14816 43 3.37 12.42     5 1.63 0.13124 And then use that current and the ECU's sensed voltage (which must be the voltage drop across the in ECU resister is there is one) to calculate the resistance of that in ECU resistor. You get:             Values in sensor   Other resistor °C ECU V sensor ohms (interpolated) Supply volts Volt drop Current   Volt Drop Resistance 58 2.68 11.85     5 2.32 0.195781   2.68 13.68879 57 2.7 11.89     5 2.3 0.19344   2.7 13.95783 56 2.74 11.93     5 2.26 0.189438   2.74 14.46381 54 2.8 12.01     5 2.2 0.183181   2.8 15.28545 49 3.06 12.208     5 1.94 0.158912   3.06 19.25592 47 3.18 12.284     5 1.82 0.14816   3.18 21.46325 43 3.37 12.42     5 1.63 0.13124   3.37 25.67816 And that's where it falls apart, because the resulting resistance would need to be the same for all of those temperatures, and it is not. So clearly the physical model is not correct. Anyway, you or someone else can use that information to go forward if someone has a better physical model. I can also show you how to interpolate for temperatures between those in the resistance chart. It's not fun because you've got to either do it like I did it for every 5°C range separately, or check to see if the slope remains constant over a wide range, then you can just work up a single formula. I'm just showing how to do it for a single 5° span. For the 58°C temperature, resistance = 11.77+2*(11.97-11.77)/5 The calc is a little arse backwards because the resistance is NTC (negative temperature coefficient), so the slope is negative, but I'm lazy, so I just treated 58 as if it was 2 degrees away from 60, not 3 degrees away from 55, and so on.
×
×
  • Create New...